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30x^2+69x+36=0
a = 30; b = 69; c = +36;
Δ = b2-4ac
Δ = 692-4·30·36
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(69)-21}{2*30}=\frac{-90}{60} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(69)+21}{2*30}=\frac{-48}{60} =-4/5 $
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